X-9+x(6+x)=x^2+4-(x+7)

Solution for X-9+x(6+x)=x^2+4-(x+7) equation:

X-9+X(6+X)=X^2+4-(X+7)

We move all terms to the left:

X-9+X(6+X)-(X^2+4-(X+7))=0

We add all the numbers together, and all the variables

X+X(X+6)-(X^2+4-(X+7))-9=0

We multiply parentheses

X^2+X+6X-(X^2+4-(X+7))-9=0


We calculate terms in parentheses: -(X^2+4-(X+7)), so:

X^2+4-(X+7)

determiningTheFunctionDomain
X^2-(X+7)+4

We get rid of parentheses

X^2-X-7+4

We add all the numbers together, and all the variables

X^2-1X-3

Back to the equation:

-(X^2-1X-3)


We add all the numbers together, and all the variables

X^2+7X-(X^2-1X-3)-9=0

We get rid of parentheses

X^2-X^2+7X+1X+3-9=0

We add all the numbers together, and all the variables

8X-6=0

We move all terms containing X to the left, all other terms to the right

8X=6

X=6/8

X=3/4